object
ParseDouble
Value Members
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final
def
!=(arg0: AnyRef): Boolean
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final
def
!=(arg0: Any): Boolean
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final
def
##(): Int
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final
def
==(arg0: AnyRef): Boolean
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final
def
==(arg0: Any): Boolean
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def
apply(str: String): Double
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final
def
asInstanceOf[T0]: T0
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def
clone(): AnyRef
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final
def
eq(arg0: AnyRef): Boolean
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def
equals(arg0: Any): Boolean
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def
finalize(): Unit
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final
def
getClass(): Class[_]
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def
hashCode(): Int
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final
def
isInstanceOf[T0]: Boolean
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final
def
ne(arg0: AnyRef): Boolean
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final
def
notify(): Unit
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final
def
notifyAll(): Unit
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final
def
synchronized[T0](arg0: ⇒ T0): T0
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def
toString(): String
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def
unapply(in: String): Option[Double]
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final
def
wait(): Unit
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final
def
wait(arg0: Long, arg1: Int): Unit
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final
def
wait(arg0: Long): Unit
Safely parse a String into a Double, avoiding the JVM bug that causes the thread to hang if the String is 2.2250738585072012e-308
This wonkaround is not recommended anymore. Instead consider using a newer version of JVM which has the necessary fix.
(Since version 2.5) Use a newer or patched JVM instead.
http://blogs.oracle.com/security/entry/security_alert_for_cve-2010-44